JEE Main Rank Predictor 2017- Predict Your Rank Now

JEE Main Rank Predictor 2017- JEE Main is the gateway for appearing in JEE Advanced to get admission into undergraduate engineering programmes offered by IITs. However, based on your JEE Main 2017 rank you’ll be eligible to get admission to NITs and several other reputed engineering colleges located across the country. If you have appeared in JEE Main 2017 and quite worried about your result then use our rank predictor tool to expect your rank.

What is Rank Predictor?

JEE Main rank predictor 2017 is an amazing tool helps students in predicting their all India rank in the exam. Probably you are aware with the fact that the CBSE gives weightage to JEE Main score and class 12th performance in 60:40 ratio. Based on this fact 99entranceexam’ rank predictor has designed which is extremely simple is use.

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How to Predict My Rank through Rank Predictor Tool?

Our rank predictor tool has developed with very simple user interface so that everyone can use it without facing any sort of hassle. While using this tool you’ll be asked to provide few information such as your actual/expected marks in class 12th or equivalent exam and expected marks in JEE Main 2017. Once you furnish these details, your rank range would be displayed on the screen.

Advantages of Using Our Rank Predictor Tool

There are so many advantages are associated with use of this tool and some of them have described below, please have a look:

  • By using this tool, candidates can easily know whether they are going to cross the prescribed JEE Main 2017 cutoff or not. Cut off is the minimum marks scored by candidates in order to qualify the test.
  • Based on predicted All India rank they can predict in which colleges they will be eligible to get admission.
  • One can easily know whether he/she is very close to his/her dream or he/she should try for next chance.

Talking about the accuracy, our experts have tried their level best to make this tool more accurate in result. Please provide genuine details for getting more efficient result.

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